Ok so if this has been talked about before in some other thread can someone post that thread here? I have been searching around for a bit now…
My question is like the title says. I have been experimenting with bho extractions for about a year now. I still can’t figure out what effects the shatter stability.
So I’m currently using W1 and ultra clear for my CRC. Using Nbutane and doing passive recovery with an injection coil. I have read and heard a lot about what effects the stability of the end product and it seems it’s mostly chopped up to the material being ran. However, on my first few runs I was using a combination of different powders like magsil and T5. Could powders play a role?
Also we don’t use a dewax chamber because we get the solvent cold as can be and use the injection coil on top of that, but I still notice some lipids in the end product. But I have seen shatter with perfect clarity assuming fats and lipids aren’t present and it still bends…
Any tips/thoughts from the best community ever would be great
@anon16547145 said it
Terpenes are a diluant to many and you can t get glass They are a liquid at room temp
Fats and waxes some are a solid at room temp and help hardening your shatter
Fine line thou to much fats and your shatter can turn opaque
Ph it seems that a slight acitic ph helps
Passing your solution treu a acitic powder gets you there
You can do some things like extract at -40C, or lower (-60C or lower for best results), perform a winterization on a product extracted at -39C and warmer, like @Roguelab said, and pass through the right powders, purge at a slightly higher temp to lower the amount of terpenes, and there’s tons more hints. tips, and tricks if you do some searching around the forum
While many people say fats/waxes play a large role in stability, I beg to differ. Even my runs that I’ve dewaxed multiple times, could come out extremely stable. Blue dream for instance, is known to be extremely stable in extract form. I’m sure fats/waxes play a role in that stability, but not as much as terpene and cannabinoid content do imo.
Basically that ensures that the carboxylic acid functionality stays protonated as THCaH instead of disassociate into THCa- and H+. I cannot really imagine a naked proton in pentane, there gotta be some amount of water molecules around to allow full separation of the two species, particularly for the proton.
If the proton doesn’t have anywhere else to go - helped by a shell or cluster of water molecules - why wouldn’t it be close to the carboxylate anion? Opposite charges attract.
Maybe the acidic conditions helps by “binding up” minute presence of water in the crystallization experiment by it having to “solvate” the added acid.
I’ll reiterate the short version, @Rowan … THCa crystallization is mediated by OH groups that can form hydrogen bonds with one another. Since each THCa molecule has two (2) OH groups that are not too close together, each THCa can H-bond to two (2) other THCa molecules, thus repeating in a lattice structure.
If other molecules with OH groups (like EtOH) or errant hydroxide ions (Bronstead base/alkali) are present, they can interfere with the THCa forming H-bonds with each other… either by solvation in the former case or by ionic disassociation in the latter.
A little bit of acid can protect against the disassociation of THCa, like @mitokid said.