Hi, new to this community, hoping I’m not doing anything wrong; if so, please correct me! Some lab experience, but none with cannabinoids or anything analytical. Just private use.
I’m pretty lost with above questions, and I’d seriously need this stuff for medical reasons.
As it is pretty much impossible for me to get a hand on normal weed, I thought about isomerizing CBD to THC. I’d buy 99,9% pure CBD crystals, and try to convert them to THC.
Considering availability, I’d have two options:
a) Use 0,005M (0,005N)? hydrochloric acid in 99,5% Ethanol. Sure less dangerous than option b. I’d dissolve the crystals in Ethanol, add the acid and (kind of) reflux (I’m afraid for ~19 hours? Can it be done quicker?) Reflux DIY with kitchen utensils mostly. As I understand it, that will only yield 60% THC, coming from a THC-free CBD powder. Am I right with this? Also, what happens with the other 40%, will they remain as CBD or degrade/get lost or whatever? I would rather have a higher rate of THC to CBD than 60:40. How much Ethanol would I need to dissolve 1 gram of CBD for the izomerisation process?
b) Second option would be petroleum ether with para-toluolsulfonic acid (would that also be 0,005 N?). I read it would yield about 90% THC which I would greatly prefer, because of price and THC:CBD ratio, but it sounds really dangerous. Luckily I wouldn’t have to extract the CBD, I’d just dissolve it in petroleum ether, add the acid and reflux for… 1 hour? two hours? Can you guys tell me how much p. ether I would need to dissolve 1 gram of CBD? If it is lots, I’d reflux as shortly as possible, neutralize and let it evaporate by itself in free air. (If I have the guts.)
Thank you so much!
K.