So I have a 440L biomass chamber and I want to flood it quick 3min approx
I have a solvent tank with more than enough solvent but I want to use a coil to cool the solvent down and have the biomass chamber flooded quick
So my question is what must be the orrifice of the coil to evacuate solvent from solvent tank to biomass chamber be to have 120 L of propane filled in 3 minutes at let’s say 8 bar (120 psi) pressure in the solvent tank and vacuum in the biomass chamber Wich is jacketed and cooled at -78C
I ll have a coil made on calculated orrifice and will then figure out what’s the length needed to get solvent to the temp I wish (-65C)
Lost as to where to start with these calculations thx @cyclopath@downtheterphole@Tech1145
I suspect @TheGratefulPhil or @Lincoln20XX are wayore qualified for that one than I….and I do recall that one of them did leave maths lying around here what are almost relevant.
These are my all-time favorite threads. Someone is going to do a chart and someone else is going to write out all the math and then someone is going to put it into excel and share it . . . my very favorite kind of thread.
I also got close to your 15 mm think Lincoln s number is gaseous form
And I checked liquid on another calculator
Pressure differential is a complex additional calculation Wich I only deducted 10%
22 mm is an additional 50% (diameter)to be sure the 40L per minute can be achieved
Damn coil is 86 meters long for a temperature drop of 65 C and I only get 1 shot to make it right
Are you using tank pressure or a liquid pump to move solvent? Your solvent tanks pressure will drop significantly as soon as you open it to the chilled coil and biomass chamber. Liquid propane will change to vapor to fill headspace in solvent tank, which will chill the tank a little and lower pressure as well. You might need to add pressure to your solvent tank (recover hot vapor) simultaneously to keep your injection rate consistent.
Energy due to height negligible, unless you just have a massive drop between orifice and chamber for shits n giggles
Vdot = 40L/min or 0.002666 m^3/s (units cancel out nicely when in m^3/s and not L/min)
Use Bernoullis to find V1, V2 is zero since propane stops at chamber. dP is 8 bar since chamber is vacuumed, I.e. pressure at point 2 is 0. Make sure units are all consistent
use Vdot = Vavg*Ac and assume that v1= Vavg
Ac is cross sectional area needed to maintain that velocity given that pressure drop, now find for diameter
Density for propane at -65C at 1 bar vs 10 bar is nearly the same, so I didn’t change density with respect to pressure since it does seem negligible but temperature taken into account.
Maybe did something wrong here but that was kinda fun
I have pumps up to 136 cfm so I guess since the tank is 3600 effective liters
This is the main solvent tank.
What’s the idea of pulling a vacuum on the tank ?
not jacketed
