@danielfp, do you think AgSil 16H is the best silicate raw material for this purpose? If not, what would you suggest?
I wonder if silicate raw material purity will impact the final product’s stability, gel time, etc. For example, do you anticipate heavy metals in AgSil 16H to act as interfering ions or otherwise affect sorbitol or carnitine chelation efficacy, stability, or strength?
Regarding AgSil 16H, is anyone aware of lab analyses for K20 and SiO2? Ideally, analysis of a few batches for batch-to-batch consistency? For example, CDFA testing shows ND for mercury, but WS State shows 0.1 ppm.
You can’t use hydrobuddy for that calculation.
For a weight/weight calculation, the easiest methods include the use of an online molar mass calculator, or simplified oxide to element conversion factors. For example, to find % K, multiply % K2O by its molar mass of K (how much K is within K2O by weight), which is 83.0148%, and divide by 100; giving a K2O to K conversion (multiplication) factor of 0.830148.
[1] For AgSil 16H, based on its label of 32% K2O and 52.8% SiO2 while using the conversion factors in the above link, contains:
- 32% K2O x 0.8301 = ~26.56% K
- 52.8% SiO2 x 0.4674 = ~24.67% Si
[2] Find the mass of K and Si within the 200 grams of AgSil 16H:
- 200 grams x 26.56% K / 100 = 53.12 grams K
- 200 grams x 24.67 % Si / 100 = 49.34 grams Si
[3] Assume 1 mL of distilled water = 1 gram. So, 500 mL weighs 500 grams.
[4] Sum the weight of the added elements (K and Si) with the water weight:
- 53.12 grams K + 49.34 grams Si + 500 grams water = 602.46 grams solution
[5] For your answer, divide the mass of K and Si in solution by the mass of the elements plus water, and multiply by 100:
- 53.12 grams K / 602.46 grams solution x 100 = ~8.82% K (w/w)
- 49.34 grams Si / 602.46 grams solution x 100 = ~8.19% Si (w/w)
Suppose you want a weight/volume calculation. In that case, you need to find the total volume of the solution (as liter) after you dissolve the potassium hydroxide and AgSil 16H. Then, follow the same steps as above. Except you would skip #3 and #4, and for #5, replace the sum of the elements and water weights with the solution volume. If you wanted to find ppm (mg/L), you would multiply the % w/v of K and Si in the solution by 10,000.
Edit
Nope, see the above math. Assuming you can trust the label on your liquid potassium silicate, your bottled product has 73.47% more K and 111.23% more Si than Daniel’s solution. That’s on a weight/weight basis because, in the US, fertilizer labels must report w/w.
Here’s how you can add approximately the same amount of Si with your product as Daniel’s “Preparation of Si solution”:
[1] Find the Si conversion factor of Daniel’s solution to your product by dividing the % Si (w/w) in Daniel’s solution by the Si in your product:
- 8.19% Si (Daniel’s solution) / 17.3% Si (your product) = 0.4734
[2] Multiply the volume of Daniel’s “Preparation of Si solution” added in step #3 of his “Preparation of stabilized monosilicic acid” SOP by the conversion factor from the above step:
- 200 mL of Daniel’s solution x 0.4734 conversion factor for your product = ~94.68 mL of your product
[3] Convert the volume of your product to mass (because it’s hard to measure 94.68 mL accurately) by mulplying the volume by your product’s density. You can often find the density in the SDS, but it’s best to measure its density. Assuming the density is 1.05 g/mL, which isn’t accurate, it’s just a number I made up:
- 94.68 mL of your product x 1.05 g/mL density of your products = ~99.41 grams of your product
[4] When replicating Daniel’s “Preparation of stabilized monosilicic acid” SOP using your potassium silicate product it’s probally best to increase its pH to 11.0-11.5 using potassium hydroxide flakes. That way you’re following his SOP very closely.
[5] At step #3, add ~99.41 grams of your product instead of 200 mL of Daniel’s solution (note that adding the potassium hydroxide to your product will reduce its % Si, but it should be negligible)