A Theory on BHO/Rosin Decarboxylation with Natural Terpene Preservation

[cyclopath]

The math has been posted here repeatedly…,
(Some of it incorrect. Which I’ve copped to.)

Presumably you’ve read this thread?

@406_Chemabis

Challenge Accepted!!!

Okay so we are gonna cook down an unknown amount of cannabis oil (THCa to THC) while trying to retain terpene profile. Ideally, the only thing we should lose is CO2 gas from the THCa → THC conversion.

Let’s say we are using 16 oz mason jars to do this in an oven set to a temperature of 250 F. The pressure rating on a 16 oz mason jar according to various sources is about 30 - 40 psi. What is the appropriate amount of input material that should be used in the sealed mason jar to fully convert the THCa to THC?

PV = nRT

P = pressure = 30 psi or 2.04 atm
V = volume = 16 oz or 0.47 L
n = moles = unknown
R = ideal gas constant = 0.08206 atmL/molek
T = temperature = 250 F or 394.3 K

Plug it all in…

PV = nRT
n = PV/RT
n = [(2.04 atm)(0.47 L)] / [(0.08206 atmL/molK)(394.3 K)]
n = 0.029632 moles CO2

@cyclopath

One mol thca == 1 mol co2

0.029632 moles CO2 = 0.029632 moles THCa

0.029632 moles THCa * 358 g/mol THCa = 10.6 g THCa

Using a 16 oz jar @ 250 F to decarb cannabis oil under pressure, you can use 10.6 g cannabis oil (abiding by the 30 psi pressure rating of the mason jar) or all the way up to 14.1 g (using the 40 psi pressure rating).

Pretty big disconnect between 10g in a 0.47 liter canning jar at 30psi and almost 30k.psi for 1000g in a 3.7liter spool.

Should be about 10x the pressure. (And is: see below).