10 l of crude lol
Based on ample experience, these are the numbers I use;
13% crude from trim and 8% doubly distilled oil from trim. For 200 lb of trim, this is about 12 and 7 kg, respectively.
OPâs assumptions are not that far off, IMO.
You get ~750g of doubly distilled oil per 20lbs of material? Thatâs pretty good, but not unbelievable either. Must be nice feedstock?
Yeah claiming yields doesnât really mean anything unless you share starting material potency.
Itâs could be impressive or it could be awful.
Yes, it was typically quite nice and extracted with warm, ca 60 psi, butane. Yielded an extract that could go straight to SPD.
First pass distillate was winterized and redistilled to afford a clear oil.
Or it might just be an observed average.
Okay so whatâs your observed average potency of input material?
We never checked the input as this was mainly pre-regulation. Typical THC content of the second pass distillate was in the high 80s.
Letâs say 88% and an overall THC molecule recovery of 90%. What does your math tell you about the input?
My math would use my yields⌠not yours which kinda of defeats the purpose.
My input can range from 5% trim up to 20% trim which I account for in my calculator and use to start my equation since Iâm testing everything before running.
They are starting to do some math over in the smash and grab thread so letâs also try here:
Letâs call the input THC content x%, meaning that 100 kg input contains x kg of THC.
I assumed an overall THC molecule recovery of 90%, meaning that the second pass clear distillate (from 100 kg input) contains 0.9x kg THC. I claimed an 8% (w/w) overall yield, 8 kg in this example, with a THC content of 88%. The second pass distillate obtained from 100 kg thus contains 7.04 kg THC.
0.9x = 7.04 â x = 7.8%
If the assumed molecule recovery was âonlyâ 75%, this would correspond to an input THC content of about 9.4%.
The point I was making was that I didnât think @Racks was that much off in his initial assumptions.